The NASA Q36 Robotic Lunar Rover can travel up to 3 hours on a single charge and has a range of 1.6 miles. After leaving its base and traveling for t hours, the speed of the Q36 is given by the function v(t)=sin√9−t2 in miles per hour. One hour into an excursion, the Q36 will have traveled 0.19655 miles. Two hours into a trip, the Q36 will have traveled 0.72421 miles.
In Lab 7, you used tangent lines to approximate the distance x(t) traveled by the Q36 Rover. Lines with slope m through the point (t0,x0) can be written in point-slope form as x=x0+m(t−t0). You used the derivative v(t)=x′(t) to find the slope at t0.
We could improve our approximations by using "best-fit parabolas." For the following problems, note that x=x0+c(t−t0)+c(t−t0)2 is the equation of a parabola that passes through the point (t0,x0). Changing the parameters m and c will change the shape of the parabola without changing the fact that it passes through that point.
Lab Preparation: Answer the following questions individually and bring your write-up to class.
-
Sketch a parabola on your large graph of x(t) that you think represents the best-fit parabola at time t0=1. Then determine the equation of this parabola using the form x=x0+m(t−t0)+c(t−t0)2 and the point (t0,x0)=(1,0.19655). To do this, find the first and second derivatives of the equation for this parabola, set x′(1)=v(1) and x″, then solve for m and c.
-
Sketch a parabola on your large graph of x(t) that you think represents the best-fit parabola at time t_0 = 2. Then determine the equation of this parabola using the form x = x_0 + m(t - t_0) + c(t - t_0)^2 and the point (t_0, x_0) = (2, 0.72421). To do this, find the first and second derivatives of the equation for this parabola, set x'(2) = v(2) and x''(2) = v'(2), then solve for m and c.
Lab: Verify that everyone in your group found the same quadratic approximations at t_0 = 1 and t_0 = 2, then answer the following questions. We encourage you to collaborate both in and out of class, but you must write up your responses individually.
-
Use your quadratic equation at time t_0 = 1 to find a more accurate approximation to the distance traveled in the 10 minutes after the t_0 = 1 hour mark (i.e., more accurate than your linear approximation in Lab 7). Then find an error bound for this approximation.
The error bound for a quadratic approximation centered at t_0 and evaluated at t is
E(t) \leq \frac{M}{6}| t - t_0|^3 \text{ where } M = \max|x''| \text{ between } t \text{ and } t_0.
(I recommend graphing x'' to determine a value for M.)
-
Use your quadratic equation at time t_0 = 2 to find a more accurate approximation to the time the rover reaches the 0.75 mile mark (i.e. more accurate than your linear approximation in Lab 7).